Nuclear research reactor of 500 KW thermal power use Uranium dioxide as fuel. Th
ID: 1409809 • Letter: N
Question
Nuclear research reactor of 500 KW thermal power use Uranium dioxide as fuel. There reactor core consists of 200 fuel element. Each fuel element has ils cooling channel. Water mass now rale inside each fuel element channel is 0.02 kg/s. The fuel element length is 0.7m. Fuel rod clad is made of Aluminum alloy. The outer diameter of the fuel element clad is 1.7cm. Clad thickness is 2.5mm. The Uranium dioxide pellets has 1.2 cm diameter. Calculate the water temperature, clad outer surface temperature. I fuel pellet outer and center temperatures at maximum clad temperature. Use the following: Cp_w 4170 J/kg.degreeC. water inlet temperature to the 45 degreeC,heat transfer coefficient,h= 500 w/m^2 degreeC,Kuo2 = 15 w/m.wegreeC, k_Al=400 w/m degreeC.Assume cosine heat flux distribution along the channel q=q_o"Cos (pi_z/L). Assume that maximum clad temperature is at 0.45 m from the coolant channel entrance and that and each fuel rod generales equal power.Explanation / Answer
Water temperature = 500 * 1000 * 0.02 * 45/4170
= 107.91 degree celsius
clad outer surface temperature = 500 * 1000 * 0.02 * 45/500
= 900 degree celsius
Fuel pellet outer temperature = 500 * 1000 * 0.02 /15
= 666.67 degree celsius
Fuel pellet centre temperature = 500 * 1000 * 0.02 * 45 * 0.45/15
= 13500 degree celsius
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