Young\'s Slit Experiment Question. Can Someone explain this to me with some deta
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Young's Slit Experiment Question. Can Someone explain this to me with some detail and important points? Thanks so much
Problem 2 Young's dou landings when the visibility is poor. Although real systems are more complicated than the example described here, they operate on the same principles. A pilot is trying to align her plane with a runway, as suggested in the Figures below. Two radio antennas Ai and A2 are positioned adjacent to the runway, separated by 40.0 m. The antennas broadcast un-modulated coherent radio waves at 27.0 MHz. The red lines in the of the radio waves exist. (a) Find the wavelength of the waves. The pilot “locks onto" the strong signal radiated along an interference maximum, and steers the plane to keep the received signal strong. If she has found the central maximum, the plane will have just the right heading to land when it reaches the runway. (b) What If? Suppose instead that the plane is flying along the first side maximum as displayed in the figure. How far to the side of the runway centerline will the plane be when it is 2.00 km from the antennas, measured along its direction of travel? (c) It is possible to tell the pilot she is on the wrong maximum by sending out two signals from each antenna and equipping the aircraft with a two-channel receiver. The ratio of the two frequencies must not be the ratio of small integers (such as 3/4). Explain how this two-frequency system would work, and why it would not ecessarily work if the ble-slit experiment underlies the Instrument Landing System used to guide aircraft to safe figure represent paths along which maxima in the interference pattern frequencies were related by an integer ratio. AiExplanation / Answer
(a) Just use the wavelength equation = c/f = 3e8m/s/25e6Hz= 12 m.
(b) We know that the first side maximum is at an angle given by d sin = (+1) , where d = 40 m. From this equation, we can obtain the value of sin = / d=12m/40m=0.3.
To obtain how far the plain will be we can use y = L sin = (2000 m) (0.3) =600 m from the centerline
(c) The purpouse is to inform the pilot about the signal that corresponds to the central maximum. The signal with = 12 m would show maxima at 0, 17.46°, 36.87°, 64.16°, and 90°. A signal of wavelength, say, 11.23 m would show maxima at 0, 16.3°, 34.2°, 57.3°. the only value in common is 0. A strong signal for both frequencies would indicate that the airplane was traveling along the central maximum; thus, straight on the runway. If 1 and 2 were related by a ratio of small integers in 1/2 = n1/n2, then the equations d sin = n2 1 and d sin = n1 2 would both be satisfied for the same nonzero angle. Thus the pilot could approach on an inappropriate bearing, and run off the runway immediately after touchdown.
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