Your friend has had a traffic accident is trying to negotiate with the insurance

Question

Your friend has had a traffic accident is trying to negotiate with the insurance company of the other driver to pay for the damage to your vehicle. She believes that the other car was going to excess speed and in addition the blame for the accident was another driver. She knows that you have the knowledge of physics and hoped that he would be able to adopt its assertion. She describes the scene of the accident and tells what you step. She was traveling to the north when I go to the fateful intersection. There was no sign of wall, so she looks in both directions and saw no carriage approximately. It was a clear day, sunny and bright. When he was in the middle of the intersection, their car was hit by the vehicle of the other driver traveling toward the east. The two cars remained united after the collision and slid to a stop. The speed limit of both highways is 50 mph. Of the visible marks on the street, you determine that after the collision carts painted 56 feet at an angle of 30 degrees north of this before stopping. She has a copy of the report of the police, which gives the brand and the year of each carriage. In the library you determine that the weight of the cart her friend is 2600lb and the other car was 2200lb, including the weight of the driver in each case. The coefficient of kinetic friction for a rubber that slips in the dry pavement is 80. It is not sufficient to prove that the other driver was traveling at high speeds.

Explanation / Answer

d = 56 ft = 56 x 0.3048m = 17.07 m

and a = - uk g = - 0.8 x 9.8 = - 7.84 m/s^2

now using vf^2 - vi^2 = 2ad

0^2 - v^2 = 2(-7.84)(17.07)

v = 16.36 m/s at an angle of 30 degree north just after the collision.

v = 16.36 ( cos30i + sin30j) = 14.17i + 8.18j m/s

now using momentum conservation,

2600v1j + 2200v2i = (2600 + 2200)(14.17i + 8.18j)

v1 = 15.10 m/s = 33.78 mph (Speed of her frend's car)

and v2 = 30.92 m/s = 69.18 mph (Speed of other car )

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