A young cyclist starts from rest at a comer and accelerated at a rate of 6m/s sq

Question

A young cyclist starts from rest at a comer and accelerated at a rate of 6m/s square for 20 sec. A. Calculate the distance and speed of the cyclist at the end of the 20 sec.she then travels at constant speed at the end of her first trip for the next 20s B. Calculate the distance she traveled
A young cyclist starts from rest at a comer and accelerated at a rate of 6m/s square for 20 sec. A. Calculate the distance and speed of the cyclist at the end of the 20 sec.she then travels at constant speed at the end of her first trip for the next 20s B. Calculate the distance she traveled
A. Calculate the distance and speed of the cyclist at the end of the 20 sec.she then travels at constant speed at the end of her first trip for the next 20s B. Calculate the distance she traveled

Explanation / Answer

A)  v = a*t (you know v at the end of the acceleration, and t= 20 seconds):

a = v/t = 6 / 30 = 0.5 m/sec^2

and with s = 1/2 a*t^2 you get the distance:

s = 1/2* 0.5*30^2 = 225 m

speed = distance/time = 225/20 = 11.25 m/sec

B) Distance traveled = speed * time

= 11.25 * 20

= 225m

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