Can someone help me with this? Physic problem. THanks Tom Brady and his team of
ID: 1410639 • Letter: C
Question
Can someone help me with this? Physic problem. THanks
Tom Brady and his team of lawyers have decided to appeal his suspension by Commissioner Roger Goodell on scientific grounds. They argue that the data analysis and conclusions brought by the NFL were false and lacked scientific rigor. You are being interviewed to demonstrate that the decrease in pressure was due solely to thermodynamic considerations. Tom would like you to answers these questions prior to a full interview in NYC for the position as scientific advisor to his legal team. NOTE: absolute pressure is 14.7 psi plus the measured value!! 10psi is actually 24.7 psi A1. Please calculate the work needed to inflate a standard NFL football from complete deflation to standard volume with regular air at standard pressure. A football has a volume of 4.2 L. Please give work values in Joules A2. Calculate the number of moles and grams of regular air that would need to be removed from the standard NFL football using the ldeal Gas Law if one was to decrease the pressure from 12.5 psi to 10.5 psi using a calibrated pressure gauge. (hint: you must convert to SI units) A3. Based on the derivation of macroscopic pressure (P) with the microscopic (Ke) characteristic of gas molecules, calculate the average velocity of N2, O2, Ar and the trace gases He and CO2 at 12.5 psi and 10.5 psi. Assume the entire footba s filled with each individual gas A4. Considering the in-door stadium temperature of 25°C and the out-door game time temperature of 10°C what is the probability of finding an N2 molecule in the highest energy state if the energy levels are at -4.5 eV and -4.0 eV (energy units are based on the energy scale versus vacuum) at game time at 10eCExplanation / Answer
A1) Work needed to inflate = F * s
= 252.4 J
A2) moles of air = PV/RT
= 1.33
=> Grams of air = moles * molecular mass
= 37.24 gm
A3) average velocity of N2 = 121.3 m/sec
average velocity of O2 = 146.5 m/sec
average velocity of Ar = 223.4 m/sec
average velocity of trace gases = 92.67 m/sec
A4) Probabilty = A * e-2kL
= 0.08852
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