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I already got these answers (below the box) and they were wrong. Please help. A

ID: 1410867 • Letter: I

Question

I already got these answers (below the box) and they were wrong. Please help.

A certain particle is sent into a uniform magnetic field, with the particle's velocity vector perpendicular to the direction of the field. The figure gives the period T of the particle's motion versus the inverse of the field magnitude B. The vertical axis scale is set by T_s= 22.4 ns, and the horizontal axis scale is set by B^-1_S = 4.4 T^-1. What is the ratio m/q of the particle's mass to the magnitude of its charge?

Explanation / Answer

1/Bs =4.4T^-1

Bs =1/4 =0.23 T

Ts=2pim/qBs

=>m/q =Ts*Bs/2pi

m/q =(22.4*10^-9)*0.23/2pi

m/q =8.20*10^-10 kg/C