In the above diagram, a ball is thrown from a ledge 100 m, above the ground as s
ID: 1411482 • Letter: I
Question
In the above diagram, a ball is thrown from a ledge 100 m, above the ground as shown, with an initial velocity of 60 m/s at an upward angle of 60 degrees. Where is the ball after 2 seconds, and what is its velocity ?(i.e., what are its x and y components of displacement, and what is the magnitude and direction of the velocity. Similarly, where is the ball after 8 seconds? What is the height of the ball at its highest point? What is the speed of the ball at its highest point? What is the speed of the ball as it passes the elevation of the ledge on its was down? What is the speed of the ball when it strikes the ground?(parts d and f, are much easier than they seem.)Explanation / Answer
a) x component dispacement = 60 * cos60 * 2
= 60 m
y component dispacement = 100 + 60 * sin60 * 2 - 0.5 * 9.8 * 2 * 2
= 184.32 m
x component velocity = 60 * cos60 = 30 m/sec
y component velocity = 60 * sin60 - 9.8 * 2
= 32.36 m/sec
=> velocity magnitude = 44.126 m/sec
b) x component dispacement = 60 * cos60 * 8
= 240 m
y component dispacement = 100 + 60 * sin60 * 8 - 0.5 * 9.8 * 8 * 8
= 202.1 m
c) height at highest point = 100 + (60 * 60 * sin60 * sin60)/2 * 9.8
= 237.755 m
d) speed at highest point = 60 * cos60 = 30 m/sec
e) speed of ball at elevation of ledge = 60 m/sec
f) horizontal speed of ball at ground = 30 m/sec
vertical speed of ball at ground = sqrt(51.962 + 2 * 9.8 * 100)
= 68.26 m/sec
=> speed of ball at ground = 74.56 m/sec
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.