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eted Chapter 2 Begin Date: 5/22/2016 12:00:00 AM Due Date: 5/28/2016 1:00:00 AM

ID: 1412274 • Letter: E

Question

eted Chapter 2 Begin Date: 5/22/2016 12:00:00 AM Due Date: 5/28/2016 1:00:00 AM End Date: 6/3/2016 12:00.00 AM (8%) Problem 12: A kangaroo can jump over an object 23 m high. 50% Part (a) Calculate its vertical speed when it leaves the ground, in meters per second 50% Part (bo How many seconds is it in the air? t 0.685 tano cotano as acoso A N 4 5 6 atan0 si 1 2 3 acotano END cosh() ODegrees Radians VO BACKSPACE DEL CIEAR give up! Feedback Feedback: s deduction per feedback. Hints: 4% deduction per hint. Hints remaining: 1 Au content o 2016 Expert TA.uc Grade Summary Potential 96% Attempts remaining (4 per attempt) 4%

Explanation / Answer

The maximum height reached by kangaroo is,

h = v^2 / 2g

Here g=9.8 m/s^2 is acceleration due to gravity

Solve for velocity v

v = sqrt ( 2gh )

v = sqrt ( 2*9.8*2.3 m)

v = 6.71 m/s

Therefore required velocity is 6.71 m/s

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(b)

Time that kangaroo is in air is,

t = 2*v / g

t = 2*6.71 m/s / 9.80 m/s^2

t = 1.17 seconds

Therefore the time of flight is 1.17 s