The following multi-hybrid cross is made: Aa BB CC Dd EE ff GG X Aa Bb CC dd EE

Question

The following multi-hybrid cross is made:

Aa BB CC Dd EE ff GG X Aa Bb CC dd EE Ff GG.

Note that the genes A, B, D, and F exhibit complete dominance (represented with capital and lower case letters), and the genes C, E, and G exhibit semidominance (aka intermediate dominance) represented with alleles with capital letters and a prime symbol.

(a) How many different genotypes might you expect to get in the offspring? (Enter your answer as a number)

(b) How many different phenotypes might you expect to get in the offspring? (Enter your answer as a number).

Explanation / Answer

Solution) In the given case of multi-hybrid:

Aa BB CC Dd EE ff GG X Aa Bb CC dd EE Ff GG.

Let's consider individual genotypes: Aa x Aa will give 3 genotypes and 2 phenotypes.

BB x Bb will give 2 genotypes and 1 phenotype.

C'C x C'C will give 3 genotypes and 3 phenotypes.

Dd x dd will give 2 genotypes and 2 phenotypes.

E'E x E'E will give 3 genotypes and 3 phenotypes.

ff x Ff will give 2 genotypes and 2 phenotypes.

G'G x G'G will give 3 genotypes and 3 phenotypes.

Therefore, total number of possible genotypes = 3 x 2 x 3 x 2 x 3 x 2 x 3 = 648

also, the possible number of phenotypes = 2 x 1 x 3 x 2 x 3 x 2 x 3 = 216.

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