Large amounts of 30 65 Zn are produced in copper exposed to accelerator beams. W

Question

Large amounts of 3065Zn are produced in copper exposed to accelerator beams. While machining contaminated copper, a physicist ingests 50x106 Ci of 3065Zn. Each 3065Zn decay emits an average -ray energy of 0.550 MeV, which is absorbed in the scientist's 75.0 kg body. What dose in rem is caused by this in one day? (Assume all of the -rays emmitted by the 3065Zn are absorbed by the physicist)

0.019

0.53

3.44

10.12

125.87

Please show working, thank you! :)

0.019

0.53

3.44

10.12

125.87

Please show working, thank you! :)

Explanation / Answer

dose in rem is caused by this in one day = (0.550 * 106 * 1.6 * 10-19) * (3065 * 105)/(50 * 10-6)

                                                               = 0.53 rem

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