A baseball is hit so that it travels straight upward after being struck by the b

Question

A baseball is hit so that it travels straight upward after being struck by the bat, A fan observes that it takes 3.00s to the ball reach its maximum height. Find (a) the ball's initial velocity and (b) the height it reaches. A stone is thrown from the top of a building upward at an angle of 30.0degree to the horizontal with an initial speed of 20.0 m/s as shown in Figure 4.13. The height from which the stone is thrown is 45.0 m above the ground A long jumper leaves the ground at an angle of 20.0degree above the horizontal and at a speed of 11.0 m/s. How far and how high does he go?

Explanation / Answer

5)

time to reach maximum height , t = 3 s

a) Using firsr equation of motion

initial velocity = g * t

initial velocity = 9.8 * 3

initial velocity = 29.4 m/s

b) let the height is h

h = 0.5 * g * t^2

h = 0.5 * 9.8 * 3^2

h= 44.1 m

the maximum height is 44.1 m

6) unknown not given

7)

theta = 20 degree

v= 11 m/s

height = v^2 * sin^2(theta)/(2 * g)

height = (11 * sin(20))^2/(2 * 9.8)

height = 0.722 m

distance far away =v^2 * sin(2 * theta)/(g)

distance far away = 11^2 * sin(2 * 20)/9.8

distance far away = 7.94 m

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