1. (a) I dive down to a depth 6.7metres beneath the surface of the ocean. Calcul

Question

1. (a) I dive down to a depth 6.7metres beneath the surface of the ocean. Calculate the pressure in Pa at that depth, assuming the density of water is 1.0×103 kg/m3, and the air pressure at the surface is 104.4 kPa

(b) Calculate the force on a door with surface area 1.04 square metres at the International Space Station. Assume the pressure inside the space station is 65.24 kPa and the pressure outside is zero.

(c) Calculate the pressure difference on the roof of a flat topped house, assuming that the air inside is stationary, and the air outside is moving at 29.9 m/s. Take the density of air to be 1.3 kg/m3

Explanation / Answer

1)

d = 6.7 m

Pressure at this depth = P0 + p * d * g

Pressure at this depth = 1.01 *10^5 + 1000 * 9.8 * 6.7

Pressure at this depth = 1.67 *10^5 Pa

b)

Force on the area = Pressure * force

Force on the area = (1.04) * (65.24 *10^3)

Force on the area = 67850 Pa

c)

pressure difference between building = 0.5 * p * v^2

pressure difference between building = 0.5 * 1.3 * 29.8^2

pressure difference between building = 577.3 Pa

the pressure difference between building is 577.3 Pa

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.