I am having trouble with the last question. A somewhat simplified model of the b
ID: 1413919 • Letter: I
Question
I am having trouble with the last question.
A somewhat simplified model of the body is sometimes used in estimating currents received by the body during electrical accidents. We'll be referring to the figure below in the A worker accidentally grabs a 110-Volt power line with both hands and stands in a puddle, effectively grounding both feet. What is the equivalent resistance of the body in this case? What is the total current passing through the torso? Assuming ground to be 0V, what is the voltage at the neck (the point where R1, R2 and R3 join)? The person manages to let go of the wire with the left hand. What happens to the following quantities? The current through the torso. The equivalent resistance used to calculate the total current. The Voltage at the hips (the point where R3, R4 and R5 join). Resistance of the torso.Explanation / Answer
when touching with both hands RH and LH same voltage
so R1 and R2 in parallel
and similarly R4 andR5 also in paralell becoz Rf and LF both touching ground
287.5 ( r1,r2 ) 120 (r3 ) 300 (r4,r5) are in series
Rnet = 707.5 ohms
v =110
current through torso = i3 = 110/707.5 = 0.15547 amp
Vh=110(where hand touching)
Vn=volatage at neck
Vh-Vn = 0.15547*287.5 = 110-Vn
V at neck = Vn= 76.802 volts
V at hip =Vh
Vh- 0 = 300*0.15547 = Vh=46.641
when LH removed
575(r1) ,120 (r3) , 300(r4,r5)
Rnet = 995 ohms equivalent resistance (INCREASED)
current through torso = 110/995 = 0.1105 amp (DECREASED)
volatage at hip Vh = 300*0.1105 = 33.15 V (DECREASED)
resistance of torso =120 OHMS (SAME)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.