One night, Jack decides to confess his love to Lucy, so he goes to her house lat

Question

One night, Jack decides to confess his love to Lucy, so he goes to her house late at night and throws a small rock at her window to get her attention. He is standing 4 meters horizontally from the side of her house and throws the rock with a speed of 14 m/s at a 65 degree angle above the horizontal. Neglecting air resistance, how high above Jack does the rock hit the side of Lucy's house? One night, Jack decides to confess his love to Lucy, so he goes to her house late at night and throws a small rock at her window to get her attention. He is standing 4 meters horizontally from the side of her house and throws the rock with a speed of 14 m/s at a 65 degree angle above the horizontal. Neglecting air resistance, how high above Jack does the rock hit the side of Lucy's house?

Explanation / Answer

Ans : The vertical height is
y(t)=17*sin(70)*t-.5*g*t^2

using the vertical velocity equation

vy(t)=17*sin(70)-g*t

when the projectile reaches apogee
vy(t)=0
t=17*sin(70)/g

plug that inot y(t) to get
y(apogee)=.5*17^2*sin^2(70)/g = 13.05 m

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