1) A charge of 7.50 C passes through a pocket calculator\'s solar cells in 3.50
ID: 1414095 • Letter: 1
Question
1) A charge of 7.50 C passes through a pocket calculator's solar cells in 3.50 h. What is the power output, given the calculator's voltage output is 3.50 V?
2) The naturally occurring charge on the ground on a fine day out in the open country is
1.00 nC/m2.
(a) What is the electric field relative to ground at a height of 5.80 m? (Indicate the direction with the sign of your answer. Assume that the positive direction is up.)
_____________ N/C
(b) Calculate the electric potential at this height.
______________ V
(c) Sketch electric field and equipotential lines for this scenario. (Submit a file with a maximum size of 1 MB.)
Explanation / Answer
1) P=VI=VQ/t=3.5*7.5/(3.5*3600)=0.00208 W
2)
a. E = sigma/2eo
E = -1*10^-9/(2*8.85*10^-12)
E = 56.49 N/C
b. potential V = Ed = 56.49* 5.8= 327.642 Volts
c) the equipotential lines are parallel to an imaginary horizontal flat sheet at different heights (potential is perpendicular to electric field)
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