A charge of 31.0 nC is placed in a uniform electric field that is directed verti

Question

A charge of 31.0 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.00 104 V/m.

A charge of 31.0 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.0o x 104 V/m (a) What work is done by the electric force when the charge moves 0.550 m to the right? (b) What work is done by the electric force when the charge moves 0.700 m upward? (c) What work is done by the electric force when the charge moves 2.90 m at an angle of 45.00 downward from the horizontal?

Explanation / Answer

(a)

Work done

W= F*d* cos

here = 90

hence, W = 0.

(b)

When charge is moving upward

W = F*d

= Q*E*d = 31*10^-9*4*10^4*0.700

= 8.68 *0^-4 J.

(c)

W = F*d* cos

= Q*E*d =- 31*10^-9*4*10^4*2.900*cos 45

= - 2.53*10^-3 J ( -ve sign for workdone by the charge)

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