A bullet is fired horizontally with an initial velocity of 800 m/s at a target l

Question

A bullet is fired horizontally with an initial velocity of 800 m/s at a target located 500 m from the rifle. How much time is required for the bullet to reach the target? How far does the bullet fall in this time? A ball rolls off a shelf what a horizontal velocity of 15 m/s. At what horizontal distance from the shelf does the ball land if it takes 0.4 s to reach the floor? A ball rolls off a table with a horizontal velocity of 16 m/s. If it takes 1.5 s for it to reach the floor: What is the vertical component of the ball's velocity just before it hits the floor? What is the horizontal component of the ball's velocity just before it hits the floor? A ball rolls off a platform that is 25 meters above the ground. The ball's horizontal velocity as it leaves the platform is 10 m/s. How much time does it take for the ball to hit the ground? How far from the base of the platform does the ball hit the ground? A projectile is fired at an angle such that the vertical componen

Explanation / Answer

Initial velocity v = 800 m/s

Distance S = 500 m

(a). Required time t = S/v

                             = 500/800

                             = 0.625 s

(b).In vertical direction :

Initial velocity u = 0

Accleration a = g = 9.8m/s 2

Time t = 0.625 s

From the relation S ' = ut +(1/2)at 2

                              = (0)(0.625)+(0.5x9.8x0.625 2)

                              = 0+1.914

                              =1.914 m

(2).Horizontal velocity v = 15 m/s

time t = 0.4 s

Required distance = v t

                           = 15 (0.4)

                           = 6 m

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