Light of a given wavelength is used to illuminate the surface of metal no photoe

Question

Light of a given wavelength is used to illuminate the surface of metal no photoelectrons are emitted. In order to cause electrons to be ejected from of this metal you should use light of a longer wavelength. use light of a shorter wavelength. use light of the same wavelength but increase its intensity. use light of the same wavelength but decrease its intensity. If the wavelength of a photon in vacuum is the same as the de Broglie of an electron, which one is traveling faster through space? The electron because it has more mass. The photon because photons always travel through space faster than electron They both have the same speed. It depends on the density of electrons Protons are being accelerated in a particle accelerator. When the protons is doubled, their de Broglie wavelength will increase by a factor of 4. increase by a factor of 2. decrease by a factor of 2. increase by a factor of squareroot 2 decrease by a factor of squareroot 2. A proton and an electron are both accelerated to the same final de Broglie wavelength of the proton and lambda_e is the Broglie wavelength then lambda_p > lambda_e

Explanation / Answer

We should use a light with lesser wavelength to reach the threshold voltage of the metal.

The photon always moves at an speed equal to C/n ,where n is the refractive index of the material.

The wavelength will decrease root times as the momentum will increase and we know , that wavelength * momentum = planks contant

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