A 0.140 kg baseball is dropped from rest. It has a speed of 1.20 m/s just before
ID: 1415219 • Letter: A
Question
A 0.140 kg baseball is dropped from rest. It has a speed of 1.20 m/s just before it hits the ground. It rebounds with a speed of 1.00 m/s. The ball is in contact with the ground for 0.0140 s. What is the average force exerted by the ground on the ball during that time? A. 22.0 N downwards B. 2.00 N downwards C. 2.00 N upwards D. 22.0 N upwards A 0.140 kg baseball is dropped from rest. It has a speed of 1.20 m/s just before it hits the ground. It rebounds with a speed of 1.00 m/s. The ball is in contact with the ground for 0.0140 s. What is the average force exerted by the ground on the ball during that time? A. 22.0 N downwards B. 2.00 N downwards C. 2.00 N upwards D. 22.0 N upwards A. 22.0 N downwards B. 2.00 N downwards C. 2.00 N upwards D. 22.0 N upwardsExplanation / Answer
Let downward direction be negative and upward be positive
vi = -1.2 m/s
vf = 1 m/s
change in momentum, p = m*(vf-vi)
= 0.140*(1 + 1.2)
= 0.308 kgm/s
t = 0.0140 s
F = change in momentum/time
= 0.308/0.0140
= 22.0 N
Since sign is positive, it will be upward
Answer: D
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