Consider the figure below. (Due to the nature of this problem, do not use rounde

Question

Consider the figure below. (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.)

http://www.webassign.net/webassignalgphys1/19-p-055.gif

(a) Find the charge stored on each capacitor in the figure shown above (C1 = 19.4 µF, C2 = 9.58 µF) when a 1.89 V battery is connected to the combination.

Q1 = ?

Q2 = ?

Q3 = ?

(b) What energy is stored in each capacitor?

E1 = ?

E2 = ?

E3 = ?

http://www.webassign.net/webassignalgphys1/19-p-055.gif

Explanation / Answer

a. by image given in (http://www.webassign.net/webassignalgphys1/19-p-055.gif) lets the battery conected at the end with series ( not specified in figure), the equivalent capacitance can be Ceq = (C'xC3)/(C'+C3) where C' = C1+C2 =19.4 +9.58 = 28.98x10^-6 F, C3= 0.300x10^-6 F

Ceq =0.297x10^-6 F

Charge Q= CeqV = 0.56 x10^-6 C, Now individual charge can be given by V'= Q/C' = .019V, and V3= Q/C= 1.87V.

Now, Q1 = C1x V' = 36.86x10^-6 C and Q2 = C2V' = 18.2x10^-6 C and Q3 =0.56 x10^-6 C.

b. Energy stored in capacitor is given by E=(1/2)Q2/C= (1/2)QV

E1 = (1/2)Q1 xV' = 35.02x10^-6 J, similary E2= 17.3 x10^-6 J and E3= 1/2 x0.56 x10^-6 x 1.87 J = 52.36 x10^-6 J.

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