Density = m/V. Pressure: P = F/A Relation between pressure and depth: P, = P, +

Question

Density = m/V. Pressure: P = F/A Relation between pressure and depth: P, = P, + gh. Continuity equation: = Bernoulli's equation: P_1 + 1/2v.^2 + gy_1 = P, + 1/2v^2_2 + gy_2. Conduction of heat: QA = (k A T)/L Stefan-Boltzmann law: Q/t = e AT^4. Ideal gas law: PV = nRT. Internal energy of a monatomic ideal gas: U = 3/2 nRT. First law of thermodynamics: U = Q - W. Efficiency of a heat engine: e = IWWQ_HJ. Efficiency of Carnot engine: e = 1 -Entropy change: S = Q_rgy/T. A scuba diver is 20 m below the surface of a fresh water lake (density of water = 1000 kg/m^3). The pressure above the surface of the water is 1 atm (1.013 x 10^5 Pa). Questions 1-7 refer to this situation. The pressure at the diver's location is approximately: Air bubbles released by the diver will ascend to the surface because of: Pascal's principle: Archimedes' principle. The continuity equation. The Bernoulli equation. As they ascend, the volume of the bubbles: If the diver were at the same depth, with the same atmospheric pressure as in question 1. but in salt water (density = 1025 kg/m^3), the pressure in the salt water would be:

Explanation / Answer

(1)
Pressure = p*g*h + 1.0 atm
Pressure = (1000*9.8*20)/101325 + 1.0 atm
Pressure = 2.93 atm

Correct option - (d)

(2)
Air bubble rises due to Archimedes Principle !!
Correct option - (b)

(3)
As the bubble rises up, pressure of liquid surrounding it reduces which is balance
by increasing its volume.
Correct option - (a) Increases

(4)
Pressure = p*g*h + 1.0 atm
Pressure = (1025*9.8*20)/101325 + 1.0 atm
Pressure in salt water = 2.98 atm

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.