A Dodge car of mass 1103 kg traveling to the right at 22.40 m/s collides head-on

Question

A Dodge car of mass 1103 kg traveling to the right at 22.40 m/s collides head-on with a Ford of mass 1258 kg traveling at the same speed but in the opposite direction. What is the speed of the Dodge the instant after the collision, assuming the collision is perfectly inelastic? In which direction will the Dodge travel the instant after the collision? In reverse of its original direction. Toward its original direction. Neither forward nor backward; its speed is 0. Suppose now that the Dodge instead had a mass of 1413 kg (but the same speed as before) Calculate its Halved the moment aft* the collision, again assuring a perfectly inelastic collusion In which direction will the Dodge travel the instant after the collision?

Explanation / Answer

First,

For perfectly inelastic collision,

m1v1i+m2v2i = (m1+m2)vf

1103*-22.40+1258*22.40 = (1103+1258)vf                 => vf= -1.47m/s

Negative sign shows direction of speed of Lodge is opposite of the original.

Second,

For perfectly inelastic collision,

m1v1i+m2v2i = (m1+m2)vf

1413*-22.40+1258*22.40 = (1103+1258)vf                 => vf= 1.3m/s

Positve sign shows direction of speed of Lodge is in the original direction.

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