1 (a) What is the change in potential energy stored in a spring when it is exten

Question

1 (a) What is the change in potential energy stored in a spring when it is extended from 1.18 cm mark on a ruler to the 26.3 cm mark? The spring constant is N/m.

(b) Calculate the length of a simple pendulum which will have a period of 1.00 seconds when the acceleration due to gravity is 9.81 m/s2.

(c) A torque is exerted on a bolt by exerting a force F1 acting in a perpendicular direction on a wrench of length L. The force is now doubled and the wrench is replaced by one that is twice as long. The force is applied in a perpendicular direction at the end of the wrench furthest from the bolt. The new torque exerted on the bolt is: Select one:

(a)

(b) 2

(c) 4

(d) 8

(a)

(b) 2

(c) 4

(d) 8

Explanation / Answer

1(a) if spring constant is k (not give)

then PE stored = k (0.263^2 - 0.118^2) /2

= 0.0276k

plug in value of k and get the answer.

(b). T = 2pi sqrt(L/g)

1 = 2 pi sqrt( L / 9.81)

L = 0.25 m

(c) t = L F1 sin90 = L F1

now L' = 2L and F1' = 2F1

t' = L' F1' sin90 = 4 L F1 = 4t

and(c)

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