Water used for low country boil is accidentally converted to steam at 400K. The
ID: 1417629 • Letter: W
Question
Water used for low country boil is accidentally converted to steam at 400K. The steam has a pressure of p=200,000Pa in a large volume of V=1000m3. What was the originalvolume of liquid water (before it turned to steam)? Use R=10J/molK, the mass density of liquid water of 1000kg/m3 and the molar mass of water M=0.02 kg/mol. (Hint: find the mass of the steam and use the density to find the volume of liquid water.)
1000 m3
100 m3
1600 m3
1m3
2 m3
A load of ice is melted entirely with a heat of Q=180,000J. If the latent heat of ice isLf=3000J/kg, what is the mass of the load of ice?
6kg
60kg
18kg
30kg
90kg
a.1000 m3
b.100 m3
c.1600 m3
d.1m3
e.2 m3
Explanation / Answer
1.from ideal gas equation
PV = n RT
PV = m/M RT ==> m= PV*MRT= 200000*1000*0.02*10*400 = 16000000000
given density of liq water is 1000 kg/m2
d = m/v ==> v= m/d = 16000000000/1000= 16000000 lt
converting lt in to m3 is 1 lt = 0.001 m3
16000000 lt = 16000 m3 ------------------>(c)
2.
Given amount of heat energy Q = 180,000 J, lanent heat of ice is Lf = 3000 J/kg
we know that when phase change , by using formula Q = mL ==> m = Q/L = 180,000/3000 = 60 kg
the load of ice needed is 60 kgs
option b is correct-------------->(b)
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