A revoliving door has four panels, equally spaced. From rest four people push th

Question

A revoliving door has four panels, equally spaced. From rest four people push the door on their respective panel. Each person pushes perpendicular to the panel. Person #1 pushes on panel #1 in a clockwise motion 1mm from the axis of rotation with a force of 10000N; person 2 pushes on panel #2 in a counter clockwise motion 10mm from the axis of rotation with a force of 1000N; person #3 pushes on panel #3 in a clockwise motion 100mm from the axis of rotation with a force of 100N. Person 4 pushes on panel #4 with in a counter clockwise motion 1000mm from the axis of rotation with a force of 10N. What is the net torque? (Answer is 0Nm show work) and what is the angular acceleration ? A revoliving door has four panels, equally spaced. From rest four people push the door on their respective panel. Each person pushes perpendicular to the panel. Person #1 pushes on panel #1 in a clockwise motion 1mm from the axis of rotation with a force of 10000N; person 2 pushes on panel #2 in a counter clockwise motion 10mm from the axis of rotation with a force of 1000N; person #3 pushes on panel #3 in a clockwise motion 100mm from the axis of rotation with a force of 100N. Person 4 pushes on panel #4 with in a counter clockwise motion 1000mm from the axis of rotation with a force of 10N. What is the net torque? (Answer is 0Nm show work) and what is the angular acceleration ?

Explanation / Answer

let clockwise motion= Positive (+)

counter clockwise motion =negative (-)

1m=1000mm

net torque= (1*10,000)+(10*1000)+(100*100)+(-1000*10)

net torque= +20,000 N mm = +20 Nm = clockwise 20 Nm

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