A patient has the following volumes of distribution: deuterium oxide: 40 liters

Question

A patient has the following volumes of distribution:

deuterium oxide: 40 liters

inulin: 13 liters

Evans blue: 2.8 liters

Her plasma shows a freezing point depression of 0.53 degrees C. For an ideal solution, a 1 OsM solution

depresses the freezing point 1.86 degrees C.

The Osmolarity calculated is 0.285 OsM

Using the data above as the initial conditions in each case, determine the effects of the following procedures on

the water and solute in the ECF and ICF after equilibrium has occurred. Give the

numerical values for volume and osmolarity of the ECF and ICF. Briefly explain your rationale for solving each

problem.

Total body

ECF

Plasma

ICF

Solute

11.4 osmol

3.705 osmol

0.798osmol

7.695 osmol

Volume

40 L

13 L

2.8 L

27 L

Osmolarity

0.285 OsM

0.285 OsM

0.285 OsM

0.285 OsM

1. . Patient ingests 1 L of water containing 0.3 moles of urea, all of which is absorbed. (Work in 2 steps)

Total body

ECF

ICF

Solute

Volume

Osmolarity

Total body

ECF

ICF

Solute

Volume

Osmolarity

Total body

ECF

Plasma

ICF

Solute

11.4 osmol

3.705 osmol

0.798osmol

7.695 osmol

Volume

40 L

13 L

2.8 L

27 L

Osmolarity

0.285 OsM

0.285 OsM

0.285 OsM

0.285 OsM

Explanation / Answer

Patient ingests 1 L of water containing 0.3 moles of urea. All of these are absorbed.

Total body:

Solute = 11.7 osmoles (11.3 + 0.3 osmoles of urea)

Volume = 41 L

Osmolarity = (41 × 0.285)/40 = 0.292 OsM

ECF:

Solute = 3.755 osmol

Volume = 13.325 L

Osmolarity = 0.292 OsM

ICF:

Solute = 7.845 osmol

Volume = 27.675 L

Osmolarity = 0.292 OsM

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