The following analysis will include calculating and formally reporting the best

Question

The following analysis will include calculating and formally reporting the best estimate of the acceleration due to gravity according to the following formula. Theta = (2pi/T)^2 L with accepted value theta_ace = 980.35 cm/s^2 Ready to be the teacher? List everything that is wrong with the following proportion of an analysis. (If you would like to use a red pen, feel free) In the end, you formally report what the result should be. theta = (2pi/T)^2 L theta = (2pi/2.7415 s)^2 185.37 cm theta = 973.6944 cm/s^2 S_0 = () squareroot (S_L/L)^2 + ( () S_T/T)^2 S_theta = () squareroot (0.140588/186.476)^2 + ( () 0.0003/2.7415)^2 cm/sec^2 S_theta = 0.00076 rightarrow 0.0008 cm/sec^2 %diff = |theta - theta_sec/theta| times 100 % diff = |973.6944 - 980.35/973.6944| times 100 %diff = 0.68% theta = 973.6944 plus minus 0.0008 %diff = 0.68%

Explanation / Answer

In error calculation , the value of SL and ST have to be taken less to account for the frictional force due to air drag .

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.