A 1.00-kg glider attached to a spring with a force constant 49.0 Nm oscillates o
ID: 1418750 • Letter: A
Question
A 1.00-kg glider attached to a spring with a force constant 49.0 Nm oscillates on a frictionless, horizontal air track. At t 0, the glider is released from rest at x -3.40 cm (that is, the spring is compressed by 340 cm). (a) Find the period of the glder's motion. (b) Find the maximum values of its speed and acceleration. m/s2 (c) Find the position, velocity, and acceleration as functions of time. (where position is in m, velocity is in m/s, acceleration is in m/s, and t is in s. use the following as necessary: t) x(t) v(t) a(t) Need Help? LRenditExplanation / Answer
part a)
m=1 kg
k=49 N/m , x=-3.4 cm=0.034 m
F=- kx= 49 * 0,034=1.66 N
T=2m/k
T=2 * 3.14 1/49
T=2 * 3.14/7
T=0.8971 sec
part b
maximum velocity= w * A
w=k/m=49/1=7
max vel=7*0.034=0.238 m/s
maximum acceleration=w2A
maximum acceleration=7 * 7* 0.034=1.666 m/s2
part c)
x(t) = Acos(t + ) = 0.034cos(wt + ) = -0.034cos(7t),
v(t) = -Asin(t + ) = 0.238sin(7t),
a(t) = -2Acos(t + ) =1.666 cos(7t).
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