A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series

Question

A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series to a 22-V battery

Part A Calculate the potential difference across each capacitor. Express your answers using two significant figures separated by a comma

Part B Calculate the charge on each capasitor. Express your answers using two significant figures separated by a comma

Part C Calculate the potential difference across each capacitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma

Part D Calculate the charge on each capasitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma.

Explanation / Answer

A) and B)   C = 1/[(1/C1) + (1/C2)] = 0.368 uF

Q = CV = 0.368*22 = 8.1 uC

Charge on each capacitor = Q = 8.1 uC

Voltage on 0.5uF capacitor = V1 = Q/C1 = 16.2 V

Voltage on 1.4uF capacitor = V1 = Q/C1 = 5.8 V

C) and D) C = C1 + C2 = 0.5+ 1.4 = 1.9 uF

Total charge = Q = CV = 1.9*22 = 41.8 uC

POtential across each capacitor = V = 22 V

Charge on C1 = Q1 = C1*V = 0.5*22 = 11 uC

Charge on C2 = Q2 = C2*V = 1.4*22 = 30.8 uC

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