Two spheres, A and B, each have an outer radius of 2.0 cm and each carry a charg

Question

Two spheres, A and B, each have an outer radius of 2.0 cm and each carry a charge of+12 nC. Sphere A is a thin conducting shell with its +12 nC charge uniformly distributed over its surface. What is the value of the electric field just outside the sphere's surface? Sphere B is a thick shell of insulating material with an inner radius of 1.0 cm, and with the +12 nC charge uniformly distributed throughout the volume of the insulating shell. What is the value of the electric field: at the inside surface of the insulating shell (at radius 1.0 cm) at the outside surface of the insulating shell (at radius 2.0 cm) at a radius of 1.5 cm.

Explanation / Answer

part a) Electric field just outside the sphere surface =q/(4oR²)

where R is the radius of the sphere and q is the charge

R=2 cm=0.02 m, , q= 12 nC=12 * 10-9 C

E=9* 109 *12 * 10-9/0.022

E=2.7 * 105N/C

Part b)

i) at the inside with r=1 cm=0.01 m

E=q/(4or²)

E=9* 109 *12 * 10-9/0.012

E= 10.8 * 10 5N/C

ii) at the ouside at R= 2 cm

E=R/3

=q/(4/3 * r3)

=12 * 10-9 /4.1 * 10-6

=2.92 * 10-3

E=R/3

E=0.02 *2.92 * 10-3/ 3* 8.85 * 10-12

E=2.1 * 106 N/C

iii) at a radius of r1=1.5

E=r1/3

E=0.015 *2.92 * 10-3/ 3* 8.85 * 10-12

E=1.6 * 106 N/C

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