A bullet of mass m 0.024 kg is moving with a velocity 2000 m/s toward a stationa

Question

A bullet of mass m 0.024 kg is moving with a velocity 2000 m/s toward a stationary cylinder of mass M 50 kg and radius R The bullet passes through the cylinder a distance 2.4 m from the the cylinder and emerges on the side of the cylinder with a speed of 200 m/s. This sets the cylinder rotating about an through other no friction, what is the angular velocity Assuming of the cylinder [15] (b) What type of collision this?work out the details of how you arrived at your answer l10] is 2000 m/s 200 m/s 2.4 m 3 m

Explanation / Answer

m = mass of bullet = 0.024 kg

M = mass of cylinder = 50 kg

R = radius of cylinder = 3 m

I = moment of inertia of cylinder = (0.5) MR2 = (0.5) (50) (3)2 = 225

w = angular velocity of cylinder

Vi = initial velocity of bullet = 2000 m/s

Vf = final velocity of bullet = 200 m/s

r = 2.4 m

Using conservation of angular momentum

m Vi r = Iw + m Vf r

0.024 (2000 - 200) (2.4) = 225 w

w = 0.46 rad/s

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