THIS IS THE Q H3 (kg) 0.1335 0.1335 0.1335 0.626 0.1335 0.1 0.15 0.1 0.25 0.15 2
ID: 1418948 • Letter: T
Question
THIS IS THE Q
H3 (kg) 0.1335 0.1335 0.1335 0.626 0.1335 0.1 0.15 0.1 0.25 0.15 2.1 3.58 2.42 0.905 2.37 2.23 0.374646 0.3550340.355034 0.351468 0.351468 0.35753 0.009733 0.468234 3.47 0.348624 0.3507890.370271 0.370271 0.372436 0.362478 0.011718 0.474714 2.36 0.317592 0.315809 0.331856 0.335422 0.32829 0.325794 0.008698 0.426671 0.8940.892 0.889 0.891 0.270266 0.271835 0.272120.272548 0.2722630.271807 0.0008991.669181 2.360.31377 0.3183280.309212 0.313770.316049 0.314226 0.00338 0.390911 2.21 3.57 2.43 2.21 3.48 2.34 2.23 3.48 2.32 2.35 2.39 2.37 Print: Change "no scaling" to "Fit Sheet on One Page" &Landscape; orientation Sine of Angle of Inclie 0.3125 0.8 Height of wood blocks under track h (m)0.25 Uncertainty in lenth h (m)| 0.01 Mass of wood block with felt (kg)0.1335 Mass of Bar(kg)0.492 Uncertainty in mass 6m (kg)0.01 Don't modify blue cells! Note that calculated values may show up as a zero or errors (e.g. #NUM!, #DIV/0!) until the appropriate data are recorded Distance between the legs of the ramp d (m) Motion Detector Frequency (Hz) Acceleration due to gravity, e (m/s9.81Explanation / Answer
As you can see from the table that
second coloum represent mass of block
last coloum represents force of friction
second-last coloum represent coefficient of friction.
Observation:
When mass of block is increased from 0.1335 to 0.626 kg, Coefficient of friction which was around 0.008 decreased to 0.0008.
So we can say that when we increase the mass of the block, coefficient of friction decreases.
Again initially force of friction was in between 0.4 to 0.5 N when mass of block was 0.1335 kg, but when mass was increased to 0.626 kg, force of friction also increased to 1.669 N
So we can say that when we increase the mass of the block, forcw of friction increases.
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