The graph shows the US Department of Labor noise regulation for working without

Question

The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 88.0 dB 2 105 95 100 Sound Level (dB) Calculate the INCREASE in the sound level from the ambient work environment level (in dB) Submit Answer Tries 0/20 A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 112 dB. By what factor does that sound intensity exceed the 2- Hours/day intensity limits from the graph? Submit Answer Tries 0/20

Explanation / Answer

dE = 10^(dB/10)

dE1 = 10^(85/10) = 3.16*10^8

dE2 = 10^(88/10) = 6.31*10^8

dE = dE1 + dE2 = (3.16 + 6.31)*10^8

dE = 9.47*10^8

dB = 10*log (dE)

dB = 10*log (9.47*10^8)

dB = 89.76 dB

increase in the sound level will be = 89.76 - 85 = 4.76 dB

2.

permissible noise exposure for 2 hours/day = 95 dB

average sound intentsity = 112 dB

difference = 112 - 95 = 17 dB

dE = 10^(dB/10)

dE = 10^(1.7) = 50.12 times greater than permissible

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