The following question present a twist on the scenario above to test your unders

Question

The following question present a twist on the scenario above to test your understanding. Suppose another stone is thrown horizontally from the same building. If it strikes the ground 66 m away, find the following values. (a) time of flight s (b) initial speed m/s (c) Speed and angle with respect to the horizontal of the velocity at impact m/s degree If the stone were thrown harder, and left with 1.5 times the initial speed, you might expect it to go farther, but how exactly does that happen? (d) Throwing the stone horizontally at 1.5 times the previous speed multiplies the time to reach the ground by what factor? (e) The horizontal component of the velocity is multiplied by what factor? (f) How many times farther does the stone land from the building?

Explanation / Answer

(a) Height of the building is not mentioned therefore asuuming = H
  time = (2H/g)1/2
(b) Distance = speed*time
   speed = 66/time
(c) When it thrown horizontally , then it makes zero degree angle with horizontal .
(d) time to reach the ground will remain same therefore multiplies with 1.
(e) By1
(f) 1.5 times

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.