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calculate the viscosity coeffcient n in poise and in pa s, if 5 gal/min flow (la

ID: 1419469 • Letter: C

Question

calculate the viscosity coeffcient n in poise and in pa s, if 5 gal/min flow (laminar) through a 6 in. long tube 1 in. inner diameter due to pressure of 18 psi and exit at 14.7 psi calculate the viscosity coeffcient n in poise and in pa s, if 5 gal/min flow (laminar) through a 6 in. long tube 1 in. inner diameter due to pressure of 18 psi and exit at 14.7 psi calculate the viscosity coeffcient n in poise and in pa s, if 5 gal/min flow (laminar) through a 6 in. long tube 1 in. inner diameter due to pressure of 18 psi and exit at 14.7 psi

Explanation / Answer

Volume flow rate = 5 gal/min = 31.545*10-5 m3/s
Area of the tube = (Pi)*(.0254/2)2 = 5.067*10-4 m2
Velocity = volume flow rate /area = 31.545*10-5 /5.067*10-4 = 0.6225 m/s
We know that for laminar flow
P1 - P2 = 32uUL / D2
where u is coefficient of viscosity , U is the average velocity , L is the length of the tube , D is the diameter of the tube
(18 - 14.7)*6894.76 = 32*u*0.622*(6*.0254) / (.0254)2
u = 4.839 Pa -s
1 pa-s = 10 Poise
therefore
u = 48.39 poise

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