A 49N (5kg) brick is placed into a pool of oil with a volume of 100L. The 5kg br

Question

A 49N (5kg) brick is placed into a pool of oil with a volume of 100L. The 5kg brick rests on the ground of the pool and is 26.51N. This raises the oil pool level to 102.5L.

The volume of oil displaced when the brick was placed in the pool is?

The volume of oil displaced is _______ the volume of the brick.

A) the same as

B) bigger than

C) smaller than

What are the forces acting on the brick when at rest on the scale at the bottom of the pool? select all that apply

A) Force of gravity

B) Normal Force

C) Buoyant Force

D) Pushing Force

The block is placed on the scale in the water. What force is read by the scale?

A) Force of gravity

B) Normal Force

C) Buoyant Force

D) Pushing Force

Explanation / Answer

The volume of oil displaced is _______ the volume of the brick.

A) the same as ( law of bouyancy)

V = Vbrick

What are the forces acting on the brick when at rest on the scale at the bottom of the pool? select all that apply

A) Force of gravity

B) Normal Force

C) Buoyant Force

The block is placed on the scale in the water. What force is read by the scale?

B) Normal Force

Here normal force = force of gravity - bouancy force

   N = m*g - rhooil*V*g

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