30-5 o-5 Energy Storage in an Electric Field ate in- 10: A parallel-plate capaci
ID: 1419843 • Letter: 3
Question
30-5 o-5 Energy Storage in an Electric Field ate in- 10: A parallel-plate capacitor is connected to an ideal battery / which provides a fixed potential difference. Originally the en- ergy stored in the capacitor is Uo. If the distance between the plates is doubled, then the new energy stored in the capacitor will be A) 4 (B) 2Up (C) Uo. (D) Uo/2. (E) U/4 he he. A parallel-plate capacitor is charged by connecting it to an ideal battery; the capacitor is then disconnected. Originally the energy stored in the capacitor is Uo. If the distance be- tween the plates is doubled, then the new energy stored in the capacitor will be a- (A) 4U (B) 2U0 (C) Uo (D) Uo/2. (E) Uo/4 12. A student originally charges a fixed capacitor to have a poten- tial energy of 1 J. If the student wishes to give the capacitor a potential energy of 4 J, then the student should at (A) quadruple the potential difference across the capacitor (B) double the potential difference across the capacitor but (C) double both the potential difference across the capaci- (D) leave the potential difference across the capacitor un- but leave the charge unchanged. leave the charge unchanged. tor and the charge. changed while doubling the charge. 13/ An inflated balloon is covered with a conducting surface that carries a charge q. The balloon develops a leak and the radius starts to decrease, but no charge is lost from the surface. (a) How does the capacitance of the balloon change as the balloon leaks? (A) C increases. (B) C decreases. (C) C remains the same. (D) There is not enough information to answer the ques- tion (b) How does the stored electrical energy change as the bal- loon leaks? (A) U increases. (B) U decreases. (C) U remains the same. (D) There is not enough information to answer the ques- tionExplanation / Answer
10) New energy stored = Uo/2
11) New energy stored = Uo
12) double both the potential difference across plates and charge .
13) C decreases .
20) charge increases .
capacitance increases .
potential difference = remain same
electric field = decreases
stored energy = increases .
22) charge increases .
capacitance increases .
potential difference = remain same
electric field = decreases
stored energy = increases .
6) a) capacitance increases
b) capacitance increases
c) capacitance increases
d) capacitance increases
e) capacitance decreases
f) capacitance remain same
g) capacitance decreases
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