The outstretched hands and arms of a figure skater preparing for a spin can be c

Q: The outstretched hands and arms of a figure skater preparing for a spin can be c

here Inital Moment of Inertia I = Io + (1/12) MR^2 I i = 0.4 + (1/12) * 8 * 1.7^2 Ii = 2.32 Kgm^2 final Moment of ineria If = IO + mr^2 If = 0.4 + 8 * 0.26^2 If = 0.9408 Kgm^2 From the law of conservation of Momentum I1 W1 = I2 W2 W2 = (2.32 * 0.3)/(0.9408) W2 = 0.74 rad/s

ID: 1420078 • Letter: T

Question

The outstretched hands and arms of a figure skater preparing for a spin can be considered a slender rod pivoting about an axis through its center (Figure 1) . When his hands and arms are brought in and wrapped around his body to execute the spin, the hands and arms can be considered a thin-walled hollow cylinder. His hands and arms have a combined mass 8.0 kg . When outstretched, they span 1.7 m ; when wrapped, they form a cylinder of radius 26 cm . The moment of inertia about the rotation axis of the remainder of his body is constant and equal to 0.40kgm2. Part A: If his original angular speed is 0.30 rev/s , what is his final angular speed? Express your answer using two significant figures.

Explanation / Answer

here

Inital Moment of Inertia I = Io + (1/12) MR^2

I i = 0.4 + (1/12) * 8 * 1.7^2

Ii = 2.32 Kgm^2

final Moment of ineria If = IO + mr^2

If = 0.4 + 8 * 0.26^2

If = 0.9408 Kgm^2

From the law of conservation of Momentum

I1 W1 = I2 W2

W2 = (2.32 * 0.3)/(0.9408)

W2 = 0.74 rad/s

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The outstretched hands and arms of a figure skater preparing for a spin can be c

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The outstretched hands and arms of a figure skater preparing for a spin can be c

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