1) A submarine dives to a depth of 500 feet. The interior of submarine is mainta
ID: 1420081 • Letter: 1
Question
1) A submarine dives to a depth of 500 feet. The interior of submarine is maintained at atmospheric pressure. What is the gauge pressure and total force applied to a hatch 2 feet by 2 feet? (assume the density of seawater is 65 lbs/ft3)
Gauge Pressure = Number psi
Applied Force = Number pounds
***prior answer given by chegg that is wrong:
1) Gauge pressure = density*g*h = 62.43*32.2*500=1005123lbf/ft3 = 6980.02psi
2)force = gauge pressure * area = 6980.02*24*24=4020491.5pounds
2) What must be the diameter of a hose if it is to deliver 5 liters of oil in 1.3 minutes with an exit velocity of 3 m/s? Pipe Diameter = milimeters
Explanation / Answer
Gauge Pressure P = rho gh
P = Dh = (65 * 500)
P = 32500 lb/ft^2
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F = PA = 32500 *2 *2
F = 130000 lb
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Volume flow rate dV/dt = AV
Q = 5/1.3 * 10^-3/60
Q =6.41 *10^-5 m^3/s
Q = AV
A = Q/V
A = 6.41*106-5/6 = 1.06 * 10^-5
A = pi*d^2/4 = 1.06* 10^-5
d = 3.67 mm
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