?A long, straight wire carrying a current of 3.40 A is placed along the axis of

Question

?A long, straight wire carrying a current of 3.40 A is placed along the axis of a cylinder of radius 0.500 m and a length of 2.40 m. Determine the total magnetic flux through the cylinder.

1. 13 points SerCP10 20.P.004 My Notes Ask Your Teacher A long, straight wire carrying a current of 3.40 A is placed along the axis of a cylinder of radius 0.500 m and a length of 2.40 m. Determine the total magnetic flux through the cylinder. T.m2 T m Need Help? Read Submit Answer Save Progress Practice Another Version

Explanation / Answer

To solve this problem, you need two formulas:
B = (N/l)(I), and = BA

1. To find the magnetic flux, you need to know the magnetic field B (generated by the current-carrying wire), and the top area of the cylinder. Apply = BA

2. B is not given. To find B, use B = (N/l)(I), (the length of the wire is the length of the cylinder, since it's placed along the axis of the cylinder.)

SO, there you go: (plug in the values you have)
B = (N/l)(I) = (4 x 10^-7 )(1/2.40 m)(3.40 A) =1.779 x 10 ^-6 T

= BA = (1.779 x 10 ^-6)(r^2) = (1.779 x 10 ^-6)(0.25) = 1.396 x 10^-6 T-M^2

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.