You have set up a laser that illuminates a single slit that is 2um (or 2000 nm)

Question

You have set up a laser that illuminates a single slit that is 2um (or 2000 nm) wide. An interference pattern is projected onto a screen. The first dark fringe is found at angle 15 degrees from the central peak.

a) Determine the wavelength of the light from the laser

b) The central maximum has a width of 1.5 cm. What is the distance between the slit and the screen?

***Please include all formulas, descriptions, explanations, etc. I really want to understand this problem and I would like to see it done step by step and an explanation for each step. Thanks.

Explanation / Answer

sintheta = lambda/a

lambda = a*sin15 = 2*10^-6*sin15 = 517 nm   <<<<<<<,----------------answer

b)

slit width

Y = 2L/a

1.5*10^-2 = 2L/(2*10^-6)

L = 1.5*10^-8 m

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