1. Displacement = 0.073 [m s-2] * Time2 + 0.38 [m] What height riser block did I
ID: 1421126 • Letter: 1
Question
1. Displacement = 0.073 [m s-2] * Time2 + 0.38 [m]
What height riser block did I use on the leg that was 1.000 meters away from the other legs? [meters] Use two significant figures in your answer. Round appropriately.
(I thought the answer was 1.5, but it's wrong)
2.
The data in the plot above has a certain trend (or best-fit) to it.
What is the slope of this data? (I thought it was 0.357, but it is wrong)
1.800 TE 1.600 1.400 1.200 Falling Dovn an Incline: Distance versus Time y = 0.3497x-0.5136 0.9836 1.000 Measured Distance Best Fit Line 0.800 0.600 0.400 0.200 average time (s) 0.000 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 8.00Explanation / Answer
Given
Y=0.073t2+0.38
V=dY/dt =2*0.073*t
acceleration
a=dV/dt =2*0.073 =0.146 m/s2
since acceleration down the ramp is
a=gh/L
=>h=aL/g =0.146*1/9.81 =0.01488 m
b)
(4.9,1.2)(5.2,1.3)
Slope
m =(1.3-1.2)/(5.2-4.9
m=0.333 m/s
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