An approximate expression for the force exerted by first rope is F =? k x + b x

Question

An approximate expression for the force exerted by first rope is

F=?kx+bx2?cx3, k = 236 N/m ,

b = 4.4 N/m2 , c = 3.7 N/m3 and x is the stretch.

Take U=0 at x=0.

Find the energy stored in stretching the rope 2.65 m .

Problem 7.33-Copy Part A An approximate expression for the force exerted by first rope is F=-kz + bz2_cz3, k=236 N/m. Find the energy stored in stretching the rope 2.65 m Express your answer using two significant figures. 4.4 N/m2 , c-3.7 N/m" and z is the Take U= 0 at z = 0. Submit My Answers Give Up

Explanation / Answer

We know that the amount of work done on the string will be stored in it as potential energy

Hence

U = Integral F.dx

=   Integral (kx+bx2cx3) dx

= (kx2/2+bx3/3cx4/4) at x = 2.65m

U = 847 J

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