There is a uniform magnetic field of magnitude 2.3 T in the +z direction. Find t

Question

There is a uniform magnetic field of magnitude 2.3 T in the +z direction. Find the force on a particle of charge 2.2 nC if its velocity is each of the following.

(a) 1.0 km/s in the y-z plane in a direction that makes an angle of 40° with the z axis (measured from the +z axis to the +y axis).

Magnitude: __________N

Direction: -x, x, -y, or y

(b) 1.0 km/s in the x-y plane in a direction that makes an angle of 40° with the x axis (measured from the +x axis to the +y axis).

Magnitude: __________N

Direction: 130 degrees relative to the +x axis in the xy-plane, 310 degrees relative to the +x axis in the xy-plane, parallel to the +x axis in the xy-plane, or parallel to the +y axis in the xy-plane

Please Show All Steps! Thanks!

Explanation / Answer

F = Q(VxB) = QVB sin(theta)

1.) F = -2.2*10^-9 (1*10^3 *2.3 sin(40) = -3.69*10^-6 N

2.)F =  -2.2*10^-9 (1*10^3 *2.3 sin(90) = -5.06*10^-6 N

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