Circular Orbit Problem At what altitude will a satellite complete a circular orb

Question

Circular Orbit Problem

At what altitude will a satellite complete a circular orbit of the Earth in 2.0h

The information i retrived so far is T=2hr = (2hours*60minutes*60secs) = (7200s)^2= 51840000s

I know that T = ((G)(M)(T^2))/((4)(pi^2))                                    exponet evaluation : -11+24+7=20

so after this information i put in r3 = [(6.67*10-11)*(5.97*1024)*(5.2*107)]/((4)*(3.14)2) =(5.25*1020)^3 im getting 1.4470*1062 This answer is not correct can you please tell me what went wrong in the problem please.

Explanation / Answer

Here ,

time period is T

T = 2 hour = 2 * 3600 s

T = 7200 s

Now , let the radius of orbit is r

T^2/r^3 = 4 *pi^2/(G * M)

(7200)^2/r^3 = 4 pi^2/(6.73 *10^-11 * 5.98 *10^24)

solving for r

r = 8.085 *10^6 m

altitude of satellite = r - radius of earth

altitude of satellite = 8.085 *10^6 - 6.673 *10^6 m

altitude of satellite = 1.412 *10^6 m

the altitude of satellite is 1.412 *10^6 m

there must be some calculation error in your amswer

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