The expression for the acceleration of the cort for the experiment you did in la

Question

The expression for the acceleration of the cort for the experiment you did in lab is a=(mg-f_)/(m_2+m_2) where m_1+m_2 is kept constant throughout. Consider the situation when friction force is zero. What is the expression for the acceleration of the cart now? (use the following as necessary:m_1, m_2 and g) D=(m_1g)/m_1+m_2) If you now have the hanging mass m_1, (som=0.5 cm), How will the value of the denominator for the expression for the acceleration change? The denominator will have in value The denominator value will be m_1/2+m_2). Halving m_1 will increase m_2 by that amount and the total mass will have a constant value as required by the experiment. What is the expression for the acceleration now? (Use the following as necessary: m_1, m_2, and g) a= Based on your answer to the previous parts, what conclusion can you draw about the acceleration of the cost? The cart's acceleration will have as the numerator in the expression for the acceleration will have when m_1 is halved The cart's acceleration will increase by a certain value but not by a factor of 1/2. Consider the situation when friction force is non-zero. What is the expression for the acceleration of the cart row? (Use the following as necessary: m_1, m_2 and g) a= If you row halve the hanging mass m_1,(so m=0.5 mg) how will the value of the denominator for the expression for the acceleration for the acceleration change? The denominator will halve in value. The denominator value will be m_1/(2+m_2). Halving m_1 will increase m_2 by shat amount and the total mass will have a constant value as required by the experiments. What is the expression for the acceleration row? (Use the following as necessary: m_1, m_2 f, and g) a= Based on your answer for the previous part, what conclusion can you draw about the acceleration of the cart? The cart's acceleration will halve as the numerator in the expression for the acceleration will halve when m_1 is halved. The cart's acceleration will remain the same as the total mass is constant during the experiment. The acceleration will increase by a certain value but not by a factor of 1/2.

Explanation / Answer

part 1 )

C option ( ideal situation )

part 6 )

the acceleration will increase by a certain value but not a factor of 1/2

because here friction is also working

a = (m1g - f ) / ( m1+m2)

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