In the following right angle. AB = 2 m. and angle ACB is 63-43 Degree. A point c

Question

In the following right angle. AB = 2 m. and angle ACB is 63-43 Degree. A point chargc of 2* 17 nC is placed at point A and another point charge -3* 17 nC is placed at point C. Calculate the POTENTIAL at B. Three charges, + 23 uC, - 23 uC and + 23 uC are placed at A (0.5cm). B (scm.o), C(-5cm,o). Calculate the potential energy of the whole system of charges. Two charges, one in at A with = 23.71 nC and other is at B with +9* 22.71 nC are M-perated by 1 m. Plod the dUtance AC in cm for which electric KOTKNTIAI. at point C is zero.

Explanation / Answer

Question 9 :

Q1 = 23 uC = 23 x 10-6 C

Q2 = - 23 uC = - 23 x 10-6 C

Q3 = 23 uC = 23 x 10-6 C

r = distance between each pair of charges = 5 cm = 0.05 m

Electric potential energy of the system is given as

U = k Q1Q2/r + k Q2 Q3 / r + k Q1 Q3/r

U = (k/r) (Q1Q2 + Q2 Q3 + Q1 Q3)

U = (9 x 109 / 0.05) (- (23 x 10-6 )2 - (23 x 10-6 )2 + (23 x 10-6 )2 )

U = - 95.2200 J

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