these are six cases for velocity vs time for objects moving along a straight, ho

Question

these are six cases for velocity vs time for objects moving along a straight, horizontal and frictionless path. a single external force acts on each object, the masses of each object are given next time the respective graph of motion. for the 4 second intervals shown, rank the work done on the objects by the external force from greatest positive to the greatest negative for cases A-F.

gative for cases A-F A +2 m/s mA = 4 kg | 0 m/s C +2 m/s mc=4kg mB = 4 kg s 4s 2s 4s 4 s -2 m/s -2m/s E +2 m/s mE = 8 kg D +2 m/s F +2 ms 4 s 2s 4s -2 m/s -2 m/s -2 ms

Explanation / Answer

Work done = Force × displacement

Fa = mass × area under v- t curve = +32

Fb = -8

Fc = +24

Fd = -64

Fe = +48

Ff = +16

Hence, greatest positive work done is E

E>A>C>F>B>D

D is the greatest negative work done.

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