If the cart now moves toward the right with an acceleration also toward the righ

Question

If the cart now moves toward the right with an acceleration also toward the right of 3.25 m/s^2. What is the mass of the cart? Show your calculations and explain d/A = 10.5/3.25 = 3.23 kg In Questions 6-8, friction may not be ignored. The force applied to the cart by spring scale F_1 is still 10.5 N. The cart now moves toward the right with a constant velocity. What are the magnitude and direction of the frictional force? Show your calculations and explain your reasoning of constant velocity, acceleration = 0 In the friction force is mass times this difference in acceleration. The force applied to the cart by spring scale F_1 is still 10.5 N. The cart now moves toward the right with an acceleration also toward the right of 1.75 m/s^2. What are the magnitude and direction of the fractional force? Show your calculations and explain. mass of kirt 3.23/10.5N mass = 5.65n/5^2 The force applied to the cart by spring scale F_1 is 10.5 N. The cart now moves towards the right with a constant velocity. The frictional force has the same magnitude as before. What does spring scale F_2 read? Show your calculations and explain.

Explanation / Answer

(6)
Friction Force = 10.5 N
Direction = Opposite the direction of motion.

(7)
Fs = ?
a = 1.75 m/s^2
m = 3.23 Kg (You have calculate that above)

F - Fs = m*a
10.5 - Fs = 3.23 *1.75
Fs = 4.85 N
Friction Force = 4.85 N

(8)

F1 = F2 + FS
10.5 = 4.85 + F2
F2 = 5.65 N
Force F2 = 5.65 N

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