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Question

ta The Expert TA Human-lik TA | Human-like https://us380k.theexpertta.com/Common/TakeTutc Settings ,nment.aspx l Help Homework 7 Begin Date: 2/13/2016 12:00:00 AM -- Due Date: 2/27/2016 12:00:00 AM End Date: 2/27/2016 12:00:00 AM (10%) Problem 10: A rod of m 0.35 kg and L = 0.55 m is on a ramp of two parallel rails with angle = 12° with respect to the horizontal. The current on the rod is I = 1.2 A, pointing into the screen as shown. A uniform magnetic field B- 0.55 T which points upward is applied in the region. Ignore the friction on the Randomized Variables ©theexpertta.com m1 = 0.35 kg L=0.55 m =12° B=0.55 T I=1.2A Assignment Status Click here for detailed view 10% Part (a) Express the magnitude of the magnetic force in terms of L, I and B D 10% Part (b) Calculate the numerical value of the magnitude of the magnetic force in N. Problem Status 10% Part (c) which direction is the magnetic force? D 10% Part (d) Express the component of the magnetic force parallel to the ramp in terms of FB and D 10% Part (e) Express the component of the weight parallel to the ramp in terms of m, g and . Take up the ramp to be positive - 10% Part (f) Calculate the numerical value of the net force F parallel to the ramp, assuming the positive direction is up the ramp in N D 10% Part (g) Express the acceleration along the ramp in terms of the F, and mt Completed Completed Completed Completed Completed Completed Completed Completed Completed 4 10% Part (h) Calculate the numerical value of a in m/s2. 10% Part (i) If a is positive, which direction does the rod go? 10% Part (j) If a is negative, which direction does the rod go? 6 Grade Summary Deductions Potential Down the ramp.OUp the ramp 0% 100% 10 Submissions Attempts remaining: 1 (100% per attempt) detailed view Submit Hint give up Hints: 0 for a 0% deduction. Hints remaining: 0 Feedback: 1% deduction per feedback

Explanation / Answer

a)
F = B*I*L*sin thetha
thetha is angle between B and I

b)
F = B*I*L*sin thetha
= 0.55*1.2*0.55*sin 90
= 0.363 N

c)
B is up
I is inward
direction of F = direction of IXB
=RIGHT
answer: right

d)
FB= 0.363 N

parallel component = FB*cos 12
= 0.363*cos 12
=0.355 N

Answer: 0.355 N

only 4 parts at a time please